Every geometry problem builds on angles and triangles. Master the key theorems, similarity rules, and area shortcuts that CAT tests every year.
Geometry begins with the simplest things: a point, a line, and an angle. But from these simple building blocks, an enormous mathematical world unfolds.
Lines form angles when they meet. Triangles are the simplest closed figure — three lines joined at three points. Yet triangles are so powerful that every polygon, every 3D shape, can be broken into triangles.
If you can master angles and triangles, you have the key to all of geometry.
Geometry appears in every CAT paper — usually 3–5 questions. Triangle properties are tested more than any other shape. They also appear embedded in circle problems, mensuration, and coordinate geometry.
| Angle | Measure |
|---|---|
| Acute | 0° to 90° |
| Right | Exactly 90° |
| Obtuse | 90° to 180° |
| Straight | Exactly 180° |
| Reflex | 180° to 360° |
| Complementary pair | Sum = 90° |
| Supplementary pair | Sum = 180° |
Vertically opposite angles (when two lines cross): always equal.
Co-interior angles (same side of transversal): sum = 180°.
Alternate angles (opposite sides of transversal): always equal.
Corresponding angles (same position at each crossing): always equal.
Sum of angles in a triangle = 180°.
Exterior angle = sum of two opposite interior angles.
| By sides | Property |
|---|---|
| Equilateral | All 3 sides equal; all angles = 60° |
| Isosceles | Two sides equal; base angles equal |
| Scalene | All sides different; all angles different |
| By angles | Property |
|---|---|
| Acute | All angles < 90° |
| Right | One angle = 90° |
| Obtuse | One angle > 90° |
For a right-angled triangle with hypotenuse c:
a² + b² = c²
Pythagorean triples (memorize these for CAT speed):
A ladder 13m long leans against a wall. Base is 5m from wall. Height reached?
h² + 5² = 13² → h² = 169-25 = 144 → h = 12m (5-12-13 triple).
Two triangles are similar if their angles are equal (shapes are same but sizes can differ).
Similar triangles have proportional sides:
If △ABC ~ △DEF, then AB/DE = BC/EF = AC/DF = k (scale factor)
Area ratio = k² (square of side ratio)
Volume ratio = k³ (for similar 3D shapes)
Tests for similarity:
In △ABC, DE ∥ BC where D is on AB and E is on AC.
AD/DB = 2/3. If BC = 15 cm, find DE.
△ADE ~ △ABC (AA: same angles since DE ∥ BC).
AD/AB = 2/5.
DE/BC = 2/5 → DE = 15 × 2/5 = 6 cm.
Theorem: The line joining midpoints of two sides of a triangle is:
Trapezoid midsegment (line joining midpoints of legs):
= (sum of parallel sides) / 2
Two triangles are congruent if they are identical in shape AND size.
| Test | Conditions |
|---|---|
| SSS | All three sides equal |
| SAS | Two sides and included angle equal |
| ASA | Two angles and included side equal |
| AAS | Two angles and any side equal |
| RHS | Right angle, hypotenuse, one side equal |
Area = ½ × base × height
Area = ½ × a × b × sin(C) [if two sides and included angle known]
Area = √[s(s-a)(s-b)(s-c)] [Heron's formula; s = semi-perimeter]
For equilateral triangle with side a:
Area = (√3/4) × a²
Height = (√3/2) × a
Triangle with sides 13, 14, 15.
s = (13+14+15)/2 = 21.
Area = √[21×(21-13)×(21-14)×(21-15)] = √[21×8×7×6] = √7056 = 84 sq units.
| Line | From | Goes to | Property |
|---|---|---|---|
| Median | Vertex | Midpoint of opposite side | Divides triangle into 2 equal areas |
| Altitude | Vertex | Opposite side (perpendicular) | Used in area calculation |
| Angle Bisector | Vertex | Opposite side | Divides opposite side in ratio of adjacent sides |
| Perpendicular Bisector | Midpoint of side | Perpendicular to side | All points equidistant from side's endpoints |
Centroid: Intersection of 3 medians. Divides each median in 2:1 (vertex:midpoint side).
Orthocenter: Intersection of 3 altitudes.
Incenter: Intersection of 3 angle bisectors. Center of incircle.
Circumcenter: Intersection of 3 perpendicular bisectors. Center of circumcircle.
If the bisector from vertex A meets BC at D:
BD/DC = AB/AC
In △ABC, AB = 6, AC = 9, BC = 10. Angle bisector from A meets BC at D. Find BD.
BD/DC = AB/AC = 6/9 = 2/3.
BD = 10 × 2/(2+3) = 10 × 2/5 = 4 units. DC = 6 units.
In any triangle:
Sum of any two sides > third side.
Difference of any two sides < third side.
This helps check if three lengths can form a triangle.
| Term | Meaning |
|---|---|
| Congruent | Identical in shape and size |
| Similar | Same shape, proportional sizes |
| Median | Line from vertex to midpoint of opposite side |
| Centroid | Meeting point of medians (2:1 ratio) |
| Incenter | Meeting point of angle bisectors (center of incircle) |
| Circumcenter | Meeting point of perpendicular bisectors |
| Heron's Formula | Area from three sides: √[s(s-a)(s-b)(s-c)] |
| Pythagoras Triple | Three integers satisfying a²+b²=c² |
❌ Confusing similar (same shape) with congruent (same shape AND size).
❌ Applying angle bisector theorem to the wrong vertex.
❌ Forgetting that the centroid is at 2/3 of each median from the vertex (not 1/2).
❌ Using Pythagoras without verifying it's a right triangle.
Angles and triangles form the geometry foundation. Key theorems: Pythagoras (right triangles), Heron's formula (area from three sides), similarity (AA, SAS, SSS), and the angle bisector theorem. Centroids, incenters, and circumcenters each have specific properties. Equilateral triangles have area (√3/4)a². Always draw the figure and identify which theorem applies before solving.
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